12x^2-308x+1326=0

Solution for 12x^2-308x+1326=0 equation:

12x^2-308x+1326=0

a = 12; b = -308; c = +1326;
Δ = b2-4ac
Δ = -3082-4·12·1326
Δ = 31216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{31216}=\sqrt{16*1951}=\sqrt{16}*\sqrt{1951}=4\sqrt{1951}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-308)-4\sqrt{1951}}{2*12}=\frac{308-4\sqrt{1951}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-308)+4\sqrt{1951}}{2*12}=\frac{308+4\sqrt{1951}}{24}
$